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Math Help - An Alphabet Puzzle

  1. #1
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    An Alphabet Puzzle

    Can anyone help me get further with this? Each of the 26 letters in the alphabet stand for a number between 1 and 26.

    I've figured out a few already but have made some assumptions.

    N x N = M
    I + C = W
    Q + J = E
    S x S = A
    D + F = R + T
    B + U = K
    O x S = V + O
    G x G = Z
    P x N = H
    Q x Q = X + L
    C + L = Y
    D + R = Z + P
    F + T = (X*2) - A
    B is lower than U
    Z x N = 50

    So far I believe that:
    A=9
    G=5
    M=4
    N=2
    Q=6
    S=3
    Z=25

    Any help towards a solution will be greatly appreciated.
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  2. #2
    Forum Admin topsquark's Avatar
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    Re: An Alphabet Puzzle

    Perhaps you could show how you got those?

    -Dan
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  3. #3
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    Re: An Alphabet Puzzle

    Since Z x N = 50, N x N = M and G x G = Z, N has to be a number that can be squared and remain under 26, while Z has to be a square number under 26 also. The factors of 50 are 1, 2, 5, 10, 25 and 50 - the only pair that satisfy these conditions is 2 x 50, so Z must be 25, leading to G being 5, while N is 2, leading to M being 4.

    S x S = A gave me 3 and 9 as the remaining square numbers under 26 are 1, 4, 9, 16 - I've already given 4 and 2 to a letter, it can't be one as that would be S x S = S, leaving just 3x3=9 for that equation.

    The assumption I've made is that Q = 6 for the phrase Q x Q = X + L; 36 I think being more likely to be reached than 49 (26+23 being the only possible combination left for that as 25 has been allocated.
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  4. #4
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    Re: An Alphabet Puzzle

    Any further thoughts?
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  5. #5
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    Re: An Alphabet Puzzle

    Bump
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  6. #6
    Forum Admin topsquark's Avatar
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    Re: An Alphabet Puzzle

    Quote Originally Posted by ThomasJPitts View Post
    Any further thoughts?
    Quote Originally Posted by ThomasJPitts View Post
    Bump
    Please do not bump your posts. It is rude.

    -Dan
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  7. #7
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    Re: An Alphabet Puzzle

    It is often acceptable in other forums I use. I apologise.
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