# An Alphabet Puzzle

• Jul 20th 2013, 08:33 AM
ThomasJPitts
An Alphabet Puzzle
Can anyone help me get further with this? Each of the 26 letters in the alphabet stand for a number between 1 and 26.

I've figured out a few already but have made some assumptions.

N x N = M
I + C = W
Q + J = E
S x S = A
D + F = R + T
B + U = K
O x S = V + O
G x G = Z
P x N = H
Q x Q = X + L
C + L = Y
D + R = Z + P
F + T = (X*2) - A
B is lower than U
Z x N = 50

So far I believe that:
A=9
G=5
M=4
N=2
Q=6
S=3
Z=25

Any help towards a solution will be greatly appreciated.
• Jul 20th 2013, 09:02 AM
topsquark
Re: An Alphabet Puzzle
Perhaps you could show how you got those?

-Dan
• Jul 20th 2013, 09:53 AM
ThomasJPitts
Re: An Alphabet Puzzle
Since Z x N = 50, N x N = M and G x G = Z, N has to be a number that can be squared and remain under 26, while Z has to be a square number under 26 also. The factors of 50 are 1, 2, 5, 10, 25 and 50 - the only pair that satisfy these conditions is 2 x 50, so Z must be 25, leading to G being 5, while N is 2, leading to M being 4.

S x S = A gave me 3 and 9 as the remaining square numbers under 26 are 1, 4, 9, 16 - I've already given 4 and 2 to a letter, it can't be one as that would be S x S = S, leaving just 3x3=9 for that equation.

The assumption I've made is that Q = 6 for the phrase Q x Q = X + L; 36 I think being more likely to be reached than 49 (26+23 being the only possible combination left for that as 25 has been allocated.
• Jul 27th 2013, 01:11 AM
ThomasJPitts
Re: An Alphabet Puzzle
Any further thoughts?
• Sep 12th 2013, 12:50 PM
ThomasJPitts
Re: An Alphabet Puzzle
Bump
• Sep 12th 2013, 07:07 PM
topsquark
Re: An Alphabet Puzzle
Quote:

Originally Posted by ThomasJPitts
Any further thoughts?

Quote:

Originally Posted by ThomasJPitts
Bump

Please do not bump your posts. It is rude.

-Dan
• Sep 12th 2013, 09:12 PM
ThomasJPitts
Re: An Alphabet Puzzle
It is often acceptable in other forums I use. I apologise.