I always get lost with this kinda thing.
Is the correct way to calculate $\displaystyle 3a^2 \rightarrow (3\times a)^2$ or $\displaystyle 3\times(a^2)$
Sorry to make a thread just for this
Thanks.
Thanks. So if I had $\displaystyle (3b)^3$ it would equal$\displaystyle 27b^3$ So you're just cubing the first term.
So if I had something like $\displaystyle (3a)^2\times(2a)^2$ it would be $\displaystyle 9a^2\times4a^2 = 36a^4$ ?
Yes!
In a sense, you have cubed the three- cubing the "b" is still "indicated"So you're just cubing the first term.
Yes, the exponent is on the parentheses so everything inside the parentheses is squared. Essentially, it is the old "order of operations", "PEDMAS": "Parentheses, then exponents, then ...." That is, you do the multiplication inside the parentheses, then do whatever is outside the parentheses.So if I had something like $\displaystyle (3a)^2\times(2a)^2$ it would be $\displaystyle 9a^2\times4a^2 = 36a^4$ ?