# Thread: Correct calculation of squares

1. ## Correct calculation of squares

I always get lost with this kinda thing.

Is the correct way to calculate $\displaystyle 3a^2 \rightarrow (3\times a)^2$ or $\displaystyle 3\times(a^2)$

Sorry to make a thread just for this

Thanks.

2. ## Re: Correct calculation of squares

Originally Posted by uperkurk
Is the correct way to calculate $\displaystyle 3a^2 \rightarrow (3\times a)^2$ or $\displaystyle 3\times(a^2)$.

Here is a hint: $\displaystyle (3a)^2=9a^2$.

3. ## Re: Correct calculation of squares

Thanks. So if I had $\displaystyle (3b)^3$ it would equal$\displaystyle 27b^3$ So you're just cubing the first term.

So if I had something like $\displaystyle (3a)^2\times(2a)^2$ it would be $\displaystyle 9a^2\times4a^2 = 36a^4$ ?

4. ## Re: Correct calculation of squares

Originally Posted by uperkurk
Thanks. So if I had $\displaystyle (3b)^3$ it would equal$\displaystyle 27b^3$
Yes!

So you're just cubing the first term.
In a sense, you have cubed the three- cubing the "b" is still "indicated"

So if I had something like $\displaystyle (3a)^2\times(2a)^2$ it would be $\displaystyle 9a^2\times4a^2 = 36a^4$ ?
Yes, the exponent is on the parentheses so everything inside the parentheses is squared. Essentially, it is the old "order of operations", "PEDMAS": "Parentheses, then exponents, then ...." That is, you do the multiplication inside the parentheses, then do whatever is outside the parentheses.