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Math Help - Correct calculation of squares

  1. #1
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    Correct calculation of squares

    I always get lost with this kinda thing.

    Is the correct way to calculate 3a^2 \rightarrow (3\times a)^2 or 3\times(a^2)

    Sorry to make a thread just for this

    Thanks.
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  2. #2
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    Re: Correct calculation of squares

    Quote Originally Posted by uperkurk View Post
    Is the correct way to calculate 3a^2 \rightarrow (3\times a)^2 or 3\times(a^2).

    Here is a hint: (3a)^2=9a^2.
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  3. #3
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    Re: Correct calculation of squares

    Thanks. So if I had (3b)^3 it would equal 27b^3 So you're just cubing the first term.

    So if I had something like (3a)^2\times(2a)^2 it would be 9a^2\times4a^2 = 36a^4 ?
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  4. #4
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    Re: Correct calculation of squares

    Quote Originally Posted by uperkurk View Post
    Thanks. So if I had (3b)^3 it would equal 27b^3
    Yes!

    So you're just cubing the first term.
    In a sense, you have cubed the three- cubing the "b" is still "indicated"

    So if I had something like (3a)^2\times(2a)^2 it would be 9a^2\times4a^2 = 36a^4 ?
    Yes, the exponent is on the parentheses so everything inside the parentheses is squared. Essentially, it is the old "order of operations", "PEDMAS": "Parentheses, then exponents, then ...." That is, you do the multiplication inside the parentheses, then do whatever is outside the parentheses.
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