I always get lost with this kinda thing.

Is the correct way to calculate $\displaystyle 3a^2 \rightarrow (3\times a)^2$ or $\displaystyle 3\times(a^2)$

Sorry to make a thread just for this (Thinking)

Thanks.

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- Jul 19th 2013, 11:02 AMuperkurkCorrect calculation of squares
I always get lost with this kinda thing.

Is the correct way to calculate $\displaystyle 3a^2 \rightarrow (3\times a)^2$ or $\displaystyle 3\times(a^2)$

Sorry to make a thread just for this (Thinking)

Thanks. - Jul 19th 2013, 11:11 AMPlatoRe: Correct calculation of squares
- Jul 19th 2013, 11:33 AMuperkurkRe: Correct calculation of squares
Thanks. So if I had $\displaystyle (3b)^3$ it would equal$\displaystyle 27b^3$ So you're just cubing the first term.

So if I had something like $\displaystyle (3a)^2\times(2a)^2$ it would be $\displaystyle 9a^2\times4a^2 = 36a^4$ ? - Jul 19th 2013, 02:29 PMHallsofIvyRe: Correct calculation of squares
Yes!

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So you're just cubing the first term.

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So if I had something like $\displaystyle (3a)^2\times(2a)^2$ it would be $\displaystyle 9a^2\times4a^2 = 36a^4$ ?

**then**do whatever is outside the parentheses.