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Math Help - Help on solving for x

  1. #1
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    Help on solving for x

    I tried doing it but I got 4. How do I begin to solve this problem?
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: Help on solving for x

    We are given:

    3x^2-2x+7=0

    The first thing I would do is subtract through by 7, then divide through by 3 to get:

    x^2-\frac{2}{3}x=-\frac{7}{3}

    Next, complete the square on the left side by adding the square of one half the coefficient of the linear term, i.e. add \left(\frac{1}{2}\cdot\frac{2}{3} \right)^2=\frac{1}{9} to get:

    x^2-\frac{2}{3}x+\frac{1}{9}=-\frac{7}{3}+\frac{1}{9}

    Rewrite the left side as the square of a binomial and combine like terms on the right, and what do you get?
    Thanks from topsquark
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