Interchangeable positions of minute hand and hour hand occur when the original interval between the two hands is 60/13 minute spaces or a multiple of this.

Could anyone explain this with examples?

Printable View

- July 7th 2013, 01:18 PMhisajeshClock problem
Interchangeable positions of minute hand and hour hand occur when the original interval between the two hands is 60/13 minute spaces or a multiple of this.

Could anyone explain this with examples? - July 7th 2013, 06:57 PMchiroRe: Clock problem
Hey hisajesh.

Can you show us what you have tried? (Hint: Try and formulate the problem in terms of congruence equations and number theory). - July 14th 2013, 08:37 PMhisajeshRe: Clock problem
I learnt congruence equation from Congruence Equation -- from Wolfram MathWorld

But I have no clue what can I do with congruence equation. - July 15th 2013, 08:40 PMhisajeshRe: Clock problem
- July 16th 2013, 11:47 AMebainesRe: Clock problem
I think the question is stated incorrectly. The hour hand and minute hand line up every 12/11 hours, or in other words after the minute hand has made 12/11 revolutions. The new position of the minute hand is therefore 1/11 further along than on the previous alignmemt, which works out to be 60/11 = 5.4545 minutes.

The derivation of the 12/11 figure come from this: the position of the minute hand is where t is in hours, and the position of the hour hand is . The hands line up when M is equal to H plus a multiple of :

where k = 1, 2, 3... This occurs when

Thus every multiple of 12/11 hours the hands are realigned, at which time the hands are 60/11 "minutes space" further on.