hi,

anyone got some ideas on figuring out this answer to the attached question.

Thanks

.

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- Jun 26th 2013, 12:33 PMSeaniboySurd Fraction
hi,

anyone got some ideas on figuring out this answer to the attached question.

Thanks

. - Jun 26th 2013, 12:38 PMadkinsjrRe: Surd Fraction
There's no question here, just a couple of equations but no statement of what to do.

- Jun 26th 2013, 01:54 PMHallsofIvyRe: Surd Fraction
I presume that the "question" is in the second, uncompleted, "equation".

If $\displaystyle x= \sqrt{k}+ \frac{1}{\sqrt{k}}+ 1$ then $\displaystyle x^2- 2x= $. Looks to me like its just a matter of doing the calculation.

$\displaystyle x^2= (\sqrt{k}+ \frac{1}{\sqrt{k}}+ 1)^2= (\sqrt{k}+ \frac{1}{\sqrt{k}})^2+ 2(\sqrt{k}+ \frac{1}{\sqrt{k}})+ 1$

$\displaystyle -2x= 2(\sqrt{k}+ \frac{1}{\sqrt{k}})+ 2$ so subtracting just gives

$\displaystyle (\sqrt{k}+ \frac{1}{\sqrt{k}})^2- 1$

Go ahead and multiply that square and see what you get. - Jun 27th 2013, 07:54 AMSeaniboyRe: Surd Fraction
Hi,

Thank you very much for taking the time to answer this question. Apologies for failure to specify question detal,l but you nailed it. Kind regards,

Sean.