Find two positive numbers that differ by 12 and have harmonic mean 5...

I started out with 1/2(1/x+12 + 1/x-12) = 1/5 but then it got all jumbled

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- Nov 4th 2007, 08:51 PMDunit0001Harmonic mean?
Find two positive numbers that differ by 12 and have harmonic mean 5...

I started out with 1/2(1/x+12 + 1/x-12) = 1/5 but then it got all jumbled - Nov 5th 2007, 02:58 AMticbol
The two positive integers:

Let x = one of them

And y = the other, and greater than x.

So,

y -x = 12

y = x +12 ---------**

Their Harmonic Mean,

H = 2 / [1/x +1/(x+12)] = 5

2 / [1/x +1/(x+12)] = 5

2/5 = 1/x +1/(x+12)

Clear the fractions, multiply both sides by 5(x)(x+12),

2(x)(x+12) = 1(5)(x+12) +1(5)(x)

2x^2+24x = 5x +60 +5x

2x^2 +24x -10x -60 = 0

2x*2 +14x -60 = 0

x^2 +7x -30 = 0

(x +10)(x -3) = 0

x = -10 or 3

Positive integer, so x = 3

y = 3 +12 = 15

Check,

2 / [1/3 +1/15] =? 5

2 / [(15 +3)/(3*15)] =? 5

2 / [18 / 45] =? 5

2(45/18) =? 5

90/18 =/ 5

5 =? 5

Yes, so, OK.

Therefore, the two positive integers are 3 and 15. --------answer.