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Math Help - Find the LCD of the Following Fractions

  1. #1
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    Find the LCD of the Following Fractions

    \frac{2a}{(3a^2 +12a + 12)b} \ \ \frac{-7b}{a(4b^2 - 8b + 4)} \ \ \frac{3}{ab^3 + 2b^3}

    The answer given by the book: 12ab^3(a+2)^2(b-1)^2

    When factoring the denominators I got the following: (3a + 6)(a + 2)b, (2b - 2)(2b - 2)a, (a + 2)b^3 edit: whoops, I wrote the 6 as a b the first time.

    I found the different factors with the highest powers to be: (3a + b)(a + 2)(2b - 2)(a)(b^3)

    I don't understand how to get from the last step I performed to the answer given in the book. I suspect I'm doing something wrong. Any help would be greatly appreciated. Thank you.
    Last edited by fogownz; June 25th 2013 at 09:18 AM.
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  2. #2
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    Re: Find the LCD of the Following Fractions

    Quote Originally Posted by fogownz View Post
    \frac{2a}{(3a^2 +12a + 12)b} \ \ \frac{-7b}{a(4b^2 - 8b + 4)} \ \ \frac{3}{ab^3 + 2b^3}
    The answer given by the book: 12ab^3(a+2)^2(b-1)^2
    Your factoring is off.

    The first denominator is 3(a+2)^2.

    The second denominator is 4a(b-1)^2.

    The third denominator is b^3(a+2).
    Thanks from fogownz and topsquark
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