Find the range of values of p for which the equation x^2 - 6x + p^2 =0 has real roots

I got till this part :

p^2 <= 9

The answer is -3<=p<=3

How do I get that? THANK YOU!

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- Jun 24th 2013, 03:09 AMpumbaa213find the range of values for p inequality question
Find the range of values of p for which the equation x^2 - 6x + p^2 =0 has real roots

I got till this part :

p^2 <= 9

The answer is -3<=p<=3

How do I get that? THANK YOU! - Jun 24th 2013, 03:13 AMPlatoRe: find the range of values for p inequality question
- Jun 24th 2013, 03:25 AMpumbaa213Re: find the range of values for p inequality question
Sorry im still unsure can you help me further? Thank you!

Why can't The answer be p<=3 OR p<= -3 ? How does it become -3<= p <= 3 ? Thank you! - Jun 24th 2013, 03:34 AMPlatoRe: find the range of values for p inequality question
- Jun 24th 2013, 04:23 AMProve ItRe: find the range of values for p inequality question
- Jun 24th 2013, 07:13 AMspacemenonRe: find the range of values for p inequality question
p^2<=9 so p<=sqrt 9 or next part we change the sign wen we take negatve sqrt 9 so p<=3 or p>=-3

-3<=p<=3 - Jun 24th 2013, 10:10 PMpumbaa213Re: find the range of values for p inequality question
Ok I ve got it..! Thanks guys! :-)