Given that lnx =1.5 and ln√y =2.2 , evaluate
(i)
(ii) 2x-y
The answer given is (i) 0.781 but i cant seem to get it.
For part (ii), im not sure how to even start.
Could somebody help me with this?
Thank you very much!
You could start by putting x and y in simple terms. So:
$\displaystyle lnx=1.5 \textup{ so }x=e^{1.5}$
$\displaystyle ln\sqrt{y}=2.2$
$\displaystyle ln(y^{\frac{1}{2}})=2.2$
$\displaystyle \frac{1}{2}lny=2.2 \textup{ so }y=e^{4.4}$