Hey pumbaa213.
Hint: ln(a) + ln(b) = ln(a * b) and ln(e^b) = b.
Solve the following equation:
ln(x^2-3x+2)=2+ln(x-1)
Im stuck on this question :/ can't seem to get the answer.
Can anyone help me with this? Thank you very much!
the answer is x=9.39
With working please. thank you!
And if anyone can correct me, here is my working:
ln(x^2-3x+2)=2+ln(x-1)
ln(x^2-3x+2)=2lne+ln(x-1)
ln(x^2-3x+2)=lne^2+ln(x-1)
and then i got lost...
Thank you!