Hey ReneG.
Hint: There is a way to factor a quartic exactly using a formula figured out a while ago.
https://en.wikipedia.org/wiki/Quarti...mula_for_roots
I am trying to factor into 4 factors to continue solving. I tried by grouping, but it didn't get me anywhere since 19 is prime (all zeros are rational). I also tried factoring out GCFs (x^{2 }and x), but to no avail.
Hey ReneG.
Hint: There is a way to factor a quartic exactly using a formula figured out a while ago.
https://en.wikipedia.org/wiki/Quarti...mula_for_roots
Try substituting various values of x, looking for a value that makes the polynomial zero.
If x=a (say) makes the polynomial zero then (x-a) will be a factor.
Factor this out and repeat the process on the lower degree polynomial.
Start with x=1,2,-1,-2,... .