I am trying to factor into 4 factors to continue solving. I tried by grouping, but it didn't get me anywhere since 19 is prime (all zeros are rational). I also tried factoring out GCFs (x^{2 }and x), but to no avail.

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- Jun 20th 2013, 09:22 PMReneGFactoring Polynomial w/ Prime Coefficient
I am trying to factor into 4 factors to continue solving. I tried by grouping, but it didn't get me anywhere since 19 is prime (all zeros are rational). I also tried factoring out GCFs (x

^{2 }and x), but to no avail. - Jun 21st 2013, 12:48 AMchiroRe: Factoring Polynomial w/ Prime Coefficient
Hey ReneG.

Hint: There is a way to factor a quartic exactly using a formula figured out a while ago.

https://en.wikipedia.org/wiki/Quarti...mula_for_roots - Jun 21st 2013, 01:00 AMBobPRe: Factoring Polynomial w/ Prime Coefficient
Try substituting various values of x, looking for a value that makes the polynomial zero.

If x=a (say) makes the polynomial zero then (x-a) will be a factor.

Factor this out and repeat the process on the lower degree polynomial.

Start with x=1,2,-1,-2,... . - Jun 21st 2013, 05:47 AMPlatoRe: Factoring Polynomial w/ Prime Coefficient