# Thread: Finding "x" in logarithms

1. ## Finding "x" in logarithms

I'm having trouble understanding how to do solve a particular type of logarithm, I don't quite understand how the rule works.

in problems like this, how would you solve for x?
$\displaystyle log_4x=3$

and this
$\displaystyle log_4{3x}=3$

2. $\displaystyle \,b > 0\,,\,\log _b x = a\quad \Rightarrow \quad x = b^a$