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Math Help - Quadratic equation question

  1. #1
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    Quadratic equation question

    If x + 1/16x = 1, then the value of 64 x^3 + 1/64^3 is

    a)4

    b)52

    c)64

    d)76
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  2. #2
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    Re: Quadratic equation question

    Is your question:

    If \displaystyle \begin{align*} x + \frac{1}{16}x = 1 \end{align*} then find the value of \displaystyle \begin{align*} 64x^3 + \frac{1}{64}x^3 \end{align*}

    or

    If \displaystyle \begin{align*} x + \frac{1}{16x} = 1 \end{align*} then find the value of \displaystyle \begin{align*} 64x^3 + \frac{1}{64x^3} \end{align*}?
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  3. #3
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    Re: Quadratic equation question

    IF x+ 1/16x = 1 then find the value of 64x^3 + 1/64x^3 is the correct question x is with 16 not 1/16 and x^3 is with 64 and not with 1/64
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  4. #4
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    Re: Quadratic equation question

    Quote Originally Posted by sscgeek View Post
    IF x+ 1/16x = 1 then find the value of 64x^3 + 1/64x^3 is the correct question x is with 16 not 1/16 and x^3 is with 64 and not with 1/64
    You still have not answered the question. Use parentheses.

    Is it 1/(16x) or is it (1/16)x?
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  5. #5
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    Re: Quadratic equation question

    1/(16x)
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  6. #6
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    Re: Quadratic equation question

    Quote Originally Posted by sscgeek View Post
    If x + 1/(16x) = 1, then the value of 64 x^3 + 1/(64x^3) is

    a)4 b)52 c)64 d)76
    \\1 = {\left( {x + \frac{1}{{16x}}} \right)^3}\\1 = {x^3} + \frac{{3x}}{{16}} + \frac{3}{{{{16}^2}x}} + \frac{1}{{{{16}^3}{x^3}}} \\1= \left( {{x^3} + \frac{1}{{{{16}^2}{x^3}}}} \right) + \frac{3}{{16}} \left( {x + \frac{1}{{16x}}} \right)

    Thus \left( {{x^3} + \frac{1}{{{{16}^2}{x^3}}}} \right) = \frac{{13}}{{16}}.

    You finish.
    Thanks from Shakarri
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  7. #7
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    Re: Quadratic equation question

    I would request you to post the question again with sufficient parenthesis to avoid confusion and better understanding.
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