1. ## Solving an equation

5/8-x=5/3x (These are both fractions)

2. 5/8=(5/3)x-x
5/8=(2/3)x
multiply by reciprocal of 2/3 to get the x on its own and you are left with
15/16=x

3. Originally Posted by Tammy07
5/8-x=5/3x (These are both fractions)
Is it possible your equation is
$\frac{5}{8 - x} = \frac{5}{3x}$?

If so, multiply both sides of the equation by $(8 - x) \cdot (3x)$ to get rid of those fractions. (And remind yourself at the end that x can't be either 0 nor 8.)

$5(3x) = 5(8 - x)$ <-- Now divide both sides by 5

$3x = 8 - x$

$4x = 8$

$x = 2$

-Dan