Since $\displaystyle \sqrt[m]{\sqrt[n]{b}} = \sqrt[mn]{b}$, how would you be able to simplify $\displaystyle \sqrt[m]{a\sqrt[n]{b}}$ whereanda are both constantsb

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- Jun 15th 2013, 12:46 AMReneGProperty of Radicals
Since $\displaystyle \sqrt[m]{\sqrt[n]{b}} = \sqrt[mn]{b}$, how would you be able to simplify $\displaystyle \sqrt[m]{a\sqrt[n]{b}}$ where

and*a***b** - Jun 15th 2013, 01:54 AMMINOANMANRe: Property of Radicals
Rene

Very simple....the variable a enters the radical and gets a power n the rest is easy.

The final answer is (mn) root(a^n x b) . - Jun 15th 2013, 05:31 AMbjhopperRe: Property of Radicals
1 remove the inner radical sign giving a*b^1/n

2 remove the outer radical sign giving a^1/m*b^1/mn - Jun 15th 2013, 07:35 AMHallsofIvyRe: Property of Radicals