• June 15th 2013, 01:46 AM
ReneG
Since $\sqrt[m]{\sqrt[n]{b}} = \sqrt[mn]{b}$, how would you be able to simplify $\sqrt[m]{a\sqrt[n]{b}}$ where a and b​ are both constants
• June 15th 2013, 02:54 AM
MINOANMAN
Rene

Very simple....the variable a enters the radical and gets a power n the rest is easy.
The final answer is (mn) root(a^n x b) .
• June 15th 2013, 06:31 AM
bjhopper
Since $\sqrt[m]{\sqrt[n]{b}} = \sqrt[mn]{b}$, how would you be able to simplify $\sqrt[m]{a\sqrt[n]{b}}$ where a and b​ are both constants
You could write it as $\sqrt[m]{a}\sqrt[mn]{b}$ or as $a^{1/m}b^{1/mn}$