1. ## simplifying algebra

ok so im new to here any help will be gratefully excepted...

a)5x + 2(2x-1) i) x + 6
b)7x - 3(2x-2) ii) 9x-1
c)4(3x-1) -6(x+1) iii)6x + 4
d) (6x-3) + (3x + 2) iv)x + 5
e)5x + 7) - (3 - x) v) 9x - 2
f)2(5x + 1) -3(3x - 1) vi) 6x - 10

so i need to know which goes with which

2. i need help soon guys

3. Look at the first one:

5x + 2(2x-1)

Just multiply out the brackets to get:

5x + 4x - 2. You can add the x terms together (5x + 4x = 9x) to give the result:

v) 9x - 2.

Just do the same thing for the other ones.

4. Yeh i knew the first one its the other im struggling with for example number 2

7x-3(2x - 2) would that mean that would be 7x - 6x - 6
which would then be x-6 which isnt there?

5. Originally Posted by pesfloyd
Yeh i knew the first one its the other im struggling with for example number 2

7x-3(2x - 2) would that mean that would be 7x - 6x - 6
which would then be x-6 which isnt there?
Check the sign on your last term:
$\displaystyle 7x - 3(2x - 2) = 7x - 3 \cdot 2x - 3 \cdot -2 = 7x - 6x + 6$

-Dan

6. Originally Posted by pesfloyd
ok so im new to here any help will be gratefully excepted...

a)5x + 2(2x-1) i) x + 6
b)7x - 3(2x-2) ii) 9x-1
c)4(3x-1) -6(x+1) iii)6x + 4
d) (6x-3) + (3x + 2) iv)x + 5
e)5x + 7) - (3 - x) v) 9x - 2
f)2(5x + 1) -3(3x - 1) vi) 6x - 10

so i need to know which goes with which
$\displaystyle A) v \because$
$\displaystyle 5x + 2(2x - 1) \therefore 9x - 2$
$\displaystyle \therefore 5x + 4x - 2$
$\displaystyle \therefore 9x - 2$

$\displaystyle B) i \because$
$\displaystyle 7x - 3(2x-2)$
$\displaystyle \therefore 7x - 6x + 6$
$\displaystyle \therefore x + 6$

$\displaystyle C) vi \because$
$\displaystyle 4(3x-1) -6(x+1) \therefore$
$\displaystyle \therefore 12x - 4 - 6x - 6$
$\displaystyle 6x -10$

$\displaystyle D) ii \because$
$\displaystyle (6x-3) + (3x + 2)$
$\displaystyle \therefore 6x - 3 + 3x + 2$
$\displaystyle \therefore 9x - 1$

$\displaystyle E)iii \because$
$\displaystyle (5x + 7) - (3 - x)$
$\displaystyle \therefore 5x + 7 - 3 + x$
$\displaystyle \therefore 6x + 4$

$\displaystyle F)iv \because$
$\displaystyle 2(5x + 1) -3(3x - 1)$
$\displaystyle \therefore 10x + 2 - 9x + 3$
$\displaystyle \therefore x + 5$