simplifying algebra

**pesfloyd** · November 4th 2007, 09:59 AM

ok so im new to here any help will be gratefully excepted...

a)5x + 2(2x-1) i) x + 6
b)7x - 3(2x-2) ii) 9x-1
c)4(3x-1) -6(x+1) iii)6x + 4
d) (6x-3) + (3x + 2) iv)x + 5
e)5x + 7) - (3 - x) v) 9x - 2
f)2(5x + 1) -3(3x - 1) vi) 6x - 10

so i need to know which goes with which

**pesfloyd** · November 4th 2007, 10:23 AM

i need help soon guys

**slevvio** · November 4th 2007, 03:59 PM

Look at the first one:

5x + 2(2x-1)

Just multiply out the brackets to get:

5x + 4x - 2. You can add the x terms together (5x + 4x = 9x) to give the result:

v) 9x - 2.

Just do the same thing for the other ones.

**pesfloyd** · November 5th 2007, 10:06 AM

Yeh i knew the first one its the other im struggling with for example number 2

7x-3(2x - 2) would that mean that would be 7x - 6x - 6
which would then be x-6 which isnt there?

**topsquark** · November 5th 2007, 10:41 AM

Originally Posted by pesfloyd

Yeh i knew the first one its the other im struggling with for example number 2

7x-3(2x - 2) would that mean that would be 7x - 6x - 6
which would then be x-6 which isnt there?

Check the sign on your last term:
$7x - 3(2x - 2) = 7x - 3 \cdot 2x - 3 \cdot -2 = 7x - 6x + 6$

-Dan

**Simplicity** · November 5th 2007, 11:13 AM

Originally Posted by pesfloyd

ok so im new to here any help will be gratefully excepted...

a)5x + 2(2x-1) i) x + 6
b)7x - 3(2x-2) ii) 9x-1
c)4(3x-1) -6(x+1) iii)6x + 4
d) (6x-3) + (3x + 2) iv)x + 5
e)5x + 7) - (3 - x) v) 9x - 2
f)2(5x + 1) -3(3x - 1) vi) 6x - 10

so i need to know which goes with which

$A) v \because$
$5x + 2(2x - 1) \therefore 9x - 2$
$\therefore 5x + 4x - 2$
$\therefore 9x - 2$

$B) i \because$
$7x - 3(2x-2)$
$\therefore 7x - 6x + 6$
$\therefore x + 6$

$C) vi \because$
$4(3x-1) -6(x+1) \therefore$
$\therefore 12x - 4 - 6x - 6$
$6x -10$

$D) ii \because$
$(6x-3) + (3x + 2)$
$\therefore 6x - 3 + 3x + 2$
$\therefore 9x - 1$

$E)iii \because$
$(5x + 7) - (3 - x)$
$\therefore 5x + 7 - 3 + x$
$\therefore 6x + 4$

$F)iv \because$
$2(5x + 1) -3(3x - 1)$
$\therefore 10x + 2 - 9x + 3$
$\therefore x + 5$

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