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Thread: Synthetic division 2

  1. #1
    Member OnMyWayToBeAMathProffesor's Avatar
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    Synthetic division 2

    sorry, this is a hard work sheet. I have another little synthetic division.

    you have to divide $\displaystyle 3x^5-3x^4+3x^2-3x+10$ by $\displaystyle x+2$. when i did this i got $\displaystyle (3x^5+3x^4+6x^3+16x^2+29x)$+$\displaystyle \frac {68}{3x^5-3x^4+3x^2-3x+10}$

    so when i do $\displaystyle ((3x^5+3x^4+6x^3+16x^2+29x)$+$\displaystyle \frac {68}{3x^5-3x^4+3x^2-3x+10}$ times $\displaystyle (x+2)$ the graph is different from $\displaystyle 3x^5-3x^4+3x^2-3x+10$, but only by a little bit. can anyone see where i messed up?

    Thank you so much and i appreciate all the help!
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  2. #2
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    earboth's Avatar
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    Quote Originally Posted by OnMyWayToBeAMathProffesor View Post
    sorry, this is a hard work sheet. I have another little synthetic division.

    you have to divide $\displaystyle 3x^5-3x^4+3x^2-3x+10$ by $\displaystyle x+2$. ...
    Hi,

    I don't know what you have actually done but your result is not correct.

    $\displaystyle (3x^5-3x^4+3x^2-3x+10) \div (x+2) = 3x^4-9x^3+18x^2-33x+63- \frac{116}{x+2}$
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  3. #3
    Member OnMyWayToBeAMathProffesor's Avatar
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    thanks

    thank you very much, i will figure it out.
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