Synthetic division 2

**OnMyWayToBeAMathProffesor** · November 4th 2007, 09:00 AM

sorry, this is a hard work sheet. I have another little synthetic division.

you have to divide $3x^5-3x^4+3x^2-3x+10$ by $x+2$ . when i did this i got $(3x^5+3x^4+6x^3+16x^2+29x)$ + $\frac {68}{3x^5-3x^4+3x^2-3x+10}$

so when i do $((3x^5+3x^4+6x^3+16x^2+29x)$ + $\frac {68}{3x^5-3x^4+3x^2-3x+10}$ times $(x+2)$ the graph is different from $3x^5-3x^4+3x^2-3x+10$ , but only by a little bit. can anyone see where i messed up?

Thank you so much and i appreciate all the help!

**earboth** · November 4th 2007, 09:31 AM

Originally Posted by OnMyWayToBeAMathProffesor

sorry, this is a hard work sheet. I have another little synthetic division.

you have to divide $3x^5-3x^4+3x^2-3x+10$ by $x+2$ . ...

Hi,

I don't know what you have actually done but your result is not correct.

$(3x^5-3x^4+3x^2-3x+10) \div (x+2) = 3x^4-9x^3+18x^2-33x+63- \frac{116}{x+2}$

**OnMyWayToBeAMathProffesor** · November 4th 2007, 11:31 AM

thank you very much, i will figure it out.

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thanks

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