# Synthetic division 2

• Nov 4th 2007, 09:00 AM
OnMyWayToBeAMathProffesor
Synthetic division 2
sorry, this is a hard work sheet. I have another little synthetic division.

you have to divide $3x^5-3x^4+3x^2-3x+10$ by $x+2$. when i did this i got $(3x^5+3x^4+6x^3+16x^2+29x)$+ $\frac {68}{3x^5-3x^4+3x^2-3x+10}$

so when i do $((3x^5+3x^4+6x^3+16x^2+29x)$+ $\frac {68}{3x^5-3x^4+3x^2-3x+10}$ times $(x+2)$ the graph is different from $3x^5-3x^4+3x^2-3x+10$, but only by a little bit. can anyone see where i messed up?

Thank you so much and i appreciate all the help!
• Nov 4th 2007, 09:31 AM
earboth
Quote:

Originally Posted by OnMyWayToBeAMathProffesor
sorry, this is a hard work sheet. I have another little synthetic division.

you have to divide $3x^5-3x^4+3x^2-3x+10$ by $x+2$. ...

Hi,

I don't know what you have actually done but your result is not correct.

$(3x^5-3x^4+3x^2-3x+10) \div (x+2) = 3x^4-9x^3+18x^2-33x+63- \frac{116}{x+2}$
• Nov 4th 2007, 11:31 AM
OnMyWayToBeAMathProffesor
thanks
thank you very much, i will figure it out.