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Math Help - Survey

  1. #1
    Newbie
    Joined
    Mar 2006
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    12

    Survey

    A survey for a group of 300 college freshman is completed with the following results: Each student is either a business major or an education major, but not both.
    45% of the group are females
    80% of the males are business majors
    Seventy-Eight (BY COUNT) of the females are education majors.

    If one student is randomly selected from the group, find the following:
    the probability that the student is a female or a business major:
    the probability that the male student is a business major;
    the probability that an education major is female
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  2. #2
    Junior Member
    Joined
    May 2005
    Posts
    60
    Not sure how to draw the table so please excuse

    Since 45% are females
    Total females = .45 x 300 = 135
    Therefore Males = 300-135 = 165
    78 females are Edn majors
    which means 135-78 = 57 are Business
    80% of males are Business Majors
    .80 x 165 = 132 Business Majors
    that gives us 165-132 = 33 Education Majors
    Education Major| Business Major
    ------------------|-----------------
    M 33 | 132
    ------------------|-----------------
    F 78 | 57

    Not sure of the first one .Sorry
    2.Male student is a business major = 132/165
    3.Education major is female = 78/(78+33)
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