# Solve the folowing system of equations

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• Jun 30th 2013, 08:36 PM
Prove It
Re: Solve the folowing system of equations
May I suggest that the mods close this thread? I read it and wanted to punch my computer screen from the OP refusing to show any effort or even bothering to thank the people who have tried to help, instead saying that what is given isn't "clear".
• Jun 30th 2013, 08:56 PM
ibdutt
Re: Solve the folowing system of equations
Quote:

Originally Posted by ibdutt
There could be a different approach. Let us see if get a different idea. In the mean time have this
Hint: recollect the definition of modulus function, |x| = x for all x >= 0 and |x| = -x for all x <0.
For second case first go by the assumption that 3x-2y+10 >0 and 2x-3y>0, then proceed by solving with elimination by substitution.

The modulus function will give us foru combinations:
for 3x-2y+10 > 0 we get |3x-2y+10| = 3x-2y+10
for 3x-2y+10 < 0 we get |3x-2y+10| = -3x+2y-10
for 2x-3y > 0 we get |2x-3y| = 2x-3y and
for 2x-3y < 0 we get |2x-3y| = -2x+3y
Using these for cases we get for four relations
x = y; x = -y; x+y = -20 and x-y = -4
We have to now use these in first equation to get the value. Remember we do not have a definite method to solve a bi-quadratic equation.
• Jun 30th 2013, 11:47 PM
thth776
Re: Solve the folowing system of equations
Quote:

Originally Posted by ibdutt
The modulus function will give us foru combinations:
for 3x-2y+10 > 0 we get |3x-2y+10| = 3x-2y+10
for 3x-2y+10 < 0 we get |3x-2y+10| = -3x+2y-10
for 2x-3y > 0 we get |2x-3y| = 2x-3y and
for 2x-3y < 0 we get |2x-3y| = -2x+3y
Using these for cases we get for four relations
x = y; x = -y; x+y = -20 and x-y = -4
We have to now use these in first equation to get the value. Remember we do not have a definite method to solve a bi-quadratic equation.

Can you speak clearly?
• Jun 30th 2013, 11:52 PM
thth776
Re: Solve the folowing system of equations
Quote:

Originally Posted by Prove It
May I suggest that the mods close this thread? I read it and wanted to punch my computer screen from the OP refusing to show any effort or even bothering to thank the people who have tried to help, instead saying that what is given isn't "clear".

Ngậm cái họng tró m lại đi nhá, ngon thì mời m giải bài nỳ, giải k đc thì lm` ơn ngậm họng tró lại, m ngon lắm hả ku? Đồ kon phò
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