1. ## Factorization

Hi there!
How does one factorize $x^3 + (x^-3) - 2$?
I tried factorizing it by $x^3 - 1 + (x^3) -1$ and a few other methods
but couldn't really get close to the answer.

Thanks

2. ## Re: Factorization

Do you mean:

$x^3+x^{-3}-2$ ?

3. ## Re: Factorization

Yeah, I actually don't know how to write mathematical formulae on the website.
All I mean is "x cube plus one upon x cube minus 2"

4. ## Re: Factorization

I'm still not sure if I interpreted your original post correctly, but if I did, then I would write:

$\frac{x^6-2x^3+1}{x^3}=\frac{(x^3)^2-2x^3+1}{x^3}$

Do you see now how the numerator is a quadratic in $x^3$? How can you factor this?