Hi there!
How does one factorize $\displaystyle x^3 + (x^-3) - 2$?
I tried factorizing it by $\displaystyle x^3 - 1 + (x^3) -1$ and a few other methods
but couldn't really get close to the answer.
Thanks
I'm still not sure if I interpreted your original post correctly, but if I did, then I would write:
$\displaystyle \frac{x^6-2x^3+1}{x^3}=\frac{(x^3)^2-2x^3+1}{x^3}$
Do you see now how the numerator is a quadratic in $\displaystyle x^3$? How can you factor this?