If log_{b}a = 0.82, then the value of log_{b}(b/a), correct to the nearest hundredth, is
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Originally Posted by alejandro If log_{b}a = 0.82, then the value of log_{b}(b/a), correct to the nearest hundredth, is You should know that log(b/a)= log(b)- log(a). And that log(b), to base b, is 1.
logb(b/a)= logb(b)- logb(a) we know that logb(b)=1 given logba = 0.82 hence, logb(b/a)= logb(b)- logb(a) = 1 - 0.82 = 0.18 Thanks HallsofIvy
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