Hi i was just wondering if its possible to get the T from the following:
ΣMA = - 4.66 × (2.5 – 0.12) − 10 × (5-1.5-0.12) + T×cos25o×0.25
+ T×sin25o×(5-0.12) = 0
If so how?
thanks
You are trying to make it too hard.
Let B = - 4.66 × (2.5 – 0.12)
Let C = − 10 × (5-1.5-0.12)
Let D = cos25o×0.25
Let E = sin25o×(5-0.12)
Then your equation reads:
which I'm sure you can solve for T.
Don't get lost in the numbers. No matter how complicated they get, they're still just numbers.
-Dan
ΣMA = - 4.66 × (2.5 – 0.12) − 10 × (5-1.5-0.12) + T×cos25o×0.25
+ T×sin25o×(5-0.12) = 0
If that is
ΣMA = - 4.66*(2.5 – 0.12) − 10*(5 -1.5 -0.12) + Tcos(25degrees)*(0.25)
+ Tsin(25deg)*(5 -0.12) = 0,
then,
4.66(2.38) -10(3.38) +T(0.25)cos(25deg) +T(4.88)sin(25deg) = 0
11.0908 -33.8 +T(0.226576947) +T(2.062377117) = 0
-22.7092 +T(2.288954064) = 0
T = 22.7092 / 2.288954064
T = 9.921212643 ---------------------answer.