# Find unknown

• Nov 3rd 2007, 01:57 AM
taurus
Find unknown
Hi i was just wondering if its possible to get the T from the following:

ΣMA = - 4.66 × (2.5 – 0.12) − 10 × (5-1.5-0.12) + T×cos25o×0.25
+ T×sin25o×(5-0.12) = 0

If so how?
thanks
• Nov 3rd 2007, 03:32 AM
topsquark
Quote:

Originally Posted by taurus
Hi i was just wondering if its possible to get the T from the following:

ΣMA = - 4.66 × (2.5 – 0.12) − 10 × (5-1.5-0.12) + T×cos25o×0.25
+ T×sin25o×(5-0.12) = 0

If so how?
thanks

You are trying to make it too hard.
Let B = - 4.66 × (2.5 – 0.12)
Let C = − 10 × (5-1.5-0.12)
Let D = cos25o×0.25
Let E = sin25o×(5-0.12)

$B + C + D \cdot T + E \cdot T = 0$
which I'm sure you can solve for T.

Don't get lost in the numbers. No matter how complicated they get, they're still just numbers.

-Dan
• Nov 3rd 2007, 04:03 AM
ticbol
ΣMA = - 4.66 × (2.5 – 0.12) − 10 × (5-1.5-0.12) + T×cos25o×0.25
+ T×sin25o×(5-0.12) = 0

If that is
ΣMA = - 4.66*(2.5 – 0.12) − 10*(5 -1.5 -0.12) + Tcos(25degrees)*(0.25)
+ Tsin(25deg)*(5 -0.12) = 0,
then,

4.66(2.38) -10(3.38) +T(0.25)cos(25deg) +T(4.88)sin(25deg) = 0
11.0908 -33.8 +T(0.226576947) +T(2.062377117) = 0
-22.7092 +T(2.288954064) = 0
T = 22.7092 / 2.288954064