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You have a circle and an ellipse there, and need to find their points of intersection. Fundamentally it is no different than other systems of two equations with two unknowns.
You continue. At the end you will find: x = 0, y = 0, xy = 9. When x = 0 => y = +-3, when y = 0 => x = +-3, when xy = 9 =>
Last edited by ManosG; May 5th 2013 at 02:26 PM.
here is my trial
Originally Posted by abualabed here is my trial You can't really get anywhere from there. The usual case for that would be that the RHS is zero. Then we could say that since ab = 0, we have that a = 0 or b = 0. But you don't have that.
ManosG's method seems to be a good one.
Hello, abualabed! . . . . . .
Subtract  - : .
Substitute into : . . . which simplifies to: . . . and which factors: .
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