# Help needed with test

• May 3rd 2013, 12:21 PM
Kendall
Help needed with test
Hi, I am new here and need your help!! I am trying to solve:
there are 15 yellow and 35 orange balls in a basket How many more yellow balls must be added to make the yellow balls 65 %
I got to this point
x + 15\x +50=65\100 and I can't move from here... Can someone guide me, please?
By the way, the answer is 50
• May 3rd 2013, 12:26 PM
dokrbb
Re: Help needed with test
Quote:

Originally Posted by Kendall
Hi, I am new here and need your help!! I am trying to solve:
there are 15 yellow and 35 orange balls in a basket How many more yellow balls must be added to make the yellow balls 65 %
I got to this point
x + 15\x +50=65\100 and I can't move from here... Can someone guide me, please?
By the way, the answer is 50

if 15 + x = 65% and 100% = (15 + x) + 35, thus

x = 100% - 50 = 50, we need to add 50,

dokrbb
• May 3rd 2013, 12:30 PM
Kendall
Re: Help needed with test
Thank you, Dokrbb!! It makes total sense! I don't know what I was thinking when did it another way!
Thank you :)
• May 3rd 2013, 03:06 PM
Soroban
Re: Help needed with test
Hello, Kendall!

Quote:

There are 15 yellow and 35 orange balls in a basket.
How many more yellow balls must be added to make the yellow balls 65% ?

Note that: $65\% \,=\,\tfrac{65}{100} \,=\,\tfrac{13}{20}$

Let $x$ = additional yellow balls.

Then the basket contains $50+x$ balls of which $15+x$ are yellow.

We want: . $\frac{x+15}{x+50} \:=\:\frac{13}{20}$ . . . . You got this far.

Cross-multiply: . $20(x+15) \:=\:13(x+50)$

n . . . . . . . . . . . $20x + 300 \:=\:13x + 650$

n . . . . . . . . . . . . . . . . . $7x \:=\:350$

. . . . . . . . . . . . . . . . . . . $x \:=\:50$
• May 3rd 2013, 04:02 PM
Wilmer
Re: Help needed with test
Since distribution does not change number of orange balls: ? + 35 = 100; ? = 65 ; 65 - 15 = 50
• May 4th 2013, 07:01 AM
topsquark
Re: Help needed with test
I realize I'm getting to this a bit late, but we aren't allowed to help with graded questions. Please do not do this again in the future! (That goes for helping the student as well, people!)

-Dan
• May 4th 2013, 07:18 AM
Kendall
Re: Help needed with test
Quote:

Originally Posted by topsquark
I realize I'm getting to this a bit late, but we aren't allowed to help with graded questions. Please do not do this again in the future! (That goes for helping the student as well, people!)

-Dan

Hi Totsquark,
Sorry I should be more clear when posted, it is not graded test, it is for practice, otherwise I wouldn't be able to ask a question, as I wouldn't have it :) We don't have assignments that we could take home...
• May 4th 2013, 07:19 AM
Kendall
Re: Help needed with test
Thank you everyone for all your help!! This board is the best!
• May 4th 2013, 08:19 AM
Wilmer
Re: Help needed with test
Quote:

Originally Posted by topsquark
I realize I'm getting to this a bit late, but we aren't allowed to help with graded questions. Please do not do this again in the future! (That goes for helping the student as well, people!)
-Dan

What's the problem Dan?
• May 4th 2013, 12:17 PM
topsquark
Re: Help needed with test
Quote:

Originally Posted by Wilmer
What's the problem Dan?

He had the final answer, not the complete solution. There's a world of difference between the two.

-Dan
• May 4th 2013, 12:35 PM
Kendall
Re: Help needed with test
Quote:

Originally Posted by topsquark
He had the final answer, not the complete solution. There's a world of difference between the two.

-Dan

OK Dan, you are making it all so difficult, sorry for even posting here, I already regret that. I explained already that it is not FOR GRADING TEST. Who would actually give us test in advance??? It just doesn't make sense... I had half of the solution and the answer, just wasn't sure about last step, please read it again.
I was very happy to find this forum and grateful for all the help, but if I am not allowed to ask questions about old test here it is fine, I will not come back here again:(
• May 4th 2013, 01:18 PM
Wilmer
Re: Help needed with test
Quote:

Originally Posted by topsquark
He had the final answer, not the complete solution. There's a world of difference between the two.

Agree. But (from what I understand from other similar sites) we do not give the
answer (50 in this case) but will "help/teach" by giving the solution steps, perhaps
using a similar problem to demonstrate.

Anyhow, ain't looking for an argument (I'm not a moderator, just an average helper).