I am currently facing a algebra question which have stumped me for days.
I try numerously but I was told that the way I done was wrong.
Can you guys lend me a hand?
I need to make
1) the subject in the equation for the first question.
2) the subject in the equation for the second question.
Both of the question uses the same equation
b = −(1010+ a)
The questions are done seperately.
Add a to both sides:
a+ b= -10 n log_10(d)
To solve for n, since -10log_10(d) is multiplied by it, divide both sides by those:
-(a+ b)/(10 log_10(d))= n
Going back to a+ b= -10 n log_10(d), to solve for d, first solve for log_10(d) by dividing both sides by -10 n to get
-(a+ b)/(10 n)= log_10(d)
and then "reverse" the logarithm by using its inverse function 10 to the power:
10^(-(a+b)/(10 n))= d