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Math Help - alternative form conversion issue

  1. #1
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    alternative form conversion issue

    Hi, I was wondering can you show me how to convert this form of the equation:

    (2 (4 n - 3 n^2))/(1 - n)^3 + (4 - 6 n)/(1 - n)^2to this form:

    (2 (n-2))/(n-1)^3Thank you
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  2. #2
    Junior Member
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    Mar 2013
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    Re: alternative form conversion issue

    \displaystyle\frac{2(4n - 3n^2)}{(1 - n)^3} + \displaystyle\frac{4 - 6n}{(1 - n)^2}

    = \displaystyle\frac{2(4n - 3n^2) + (4 -6n)(1 - n)}{(1 - n)^3}

    = \displaystyle\frac{8n - 6n^2 + 4 - 10n + 6n^2}{(1 - n)^3} = \displaystyle\frac{4 - 2n}{(1 - n)^3} = \displaystyle\frac{2(n - 2)}{(1 - n)^3}
    Thanks from technopersia
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