how do you solve for R, rate in this equation

please provide a "check" that shows how to solve the problem

Formula

I = G/(1+r) + G/(1+r)^2 + G/(1+r)^3

Given

I=100,000

G=40211 (which is from the fact that 120634/3 = 40211)

Solve for R100,000 = 40211/(1+r) + 40211/(1+r)^2 + P/(1+r)^3

About question

this problem is supposed show how a stream of 120634 divided into 3 equal payments of 40211 can yield the same rate of return of 100,000 with respect to the rate of return. we are solving for the rate of return.

120634/3 = 40211 = G

I know the answer for r, but I need to understand the algebraic concepts that arrive at the conclusion. (the answer is R = .10, this was done by inputing values)

I = 100,000 = 40211/(1.1)^1 + 40211/(1.1)^2 + 40211/(1.1)^3

I need to know how to solve for the rate rwhich is equal to 0.1.

(1+r) = 1.1

I'm having difficulty solving this problem because I do not know how tosimplify the exponents for the term involving the variable (1+R).

This problem is difficult because the term 1+r is repeated three times, and each time to a higher consective exponent. I do not know how to simplify such a complex term.

I do know how to simplify the exponent we use log, but having three terms complicates things for me, so I need some help.

This is a algebra problem involving exponents, but here we want to solve for the rate, R, by showing a check.

Work Done So far (has errors)A = p/(1+r) + p(1+r)^2 + p(1+r)^3120634/3 = 40211

100000 = 40211/(1+r) + 40211/(1+r)^2 + 40211/(1+r)^3

ln 100000/40211 = ln40211/ln(1+r) + ln40211/ln(1+r)^2 + ln40211/ln(1+r)^3

5 = ln40211/ln(1+r) + ln40211/ln(1+r)^2 + ln40211/ln(1+r)^3

5 = ln40211/ln(1+r) + 40211/2ln(1+r) + ln40211/3ln(1+r)

5/ln(1+r) = ln40211/1 + ln40211/2 + ln40211/3

1/ln(1+r) = ln40211/5 + ln40211/10 + ln40211/15

ln(1+r) = 5/ln(40211) + 10/ln(40211) + 15/ln(40211)

ln(1+r) = 2.82968

1+r = 16.94

r = 15.94

15.94 is not correct. the answer should be 0.10 resulting in 10%

If someone can help point out where my approach was wrong.

Another approach is considering that 1/(1+r) = 1+r^-1, but I arrived at the same answers. I think there is a error in my use of the Ln function

As you can see I need some clarification on the logarthim rules for algebra

If someone can provide a check, That would be very much appreciated

PSI need to know how to solve for this problem, because on the test they will not tell me what the rate is equal to, so this is similar to the compound interest formula, but here we solve for rate, and rate is complicated by the fact that it is in the denominator, it is repeated, and it is taken the consective higher exponent.