working with a second degree equation of the type , you normally use
the sign shows that you may have two(2) roots for this equation and this depends on the values of the discriminant
now just plug in the values and do the math,
dokrbb
Ok so the question is as follows: solve for y
y^2 + 6y + 9 = 0
I don't know if I'm correct but so far this is what I've got
y^2 + 6y = -9
y^2 + y = -9
6
y^2 + y= -1.5
I don't know if there's a way to type to the second on here?? so ^2 will do for now
working with a second degree equation of the type , you normally use
the sign shows that you may have two(2) roots for this equation and this depends on the values of the discriminant
now just plug in the values and do the math,
dokrbb
This particular question you can also do by splitting the middle term. the algorithm is
for ax^2+ bx + c = 0; find the product ac which in this case is 9. next find such factors of this product such that their sum is b, the coefficient of x. in this case 9 = 3 x 3 and 3 + 3 = 6
rewrite the equation with middle term as the sum.
i.e., y^2+ 3y + 3y = 9=0
Now take common and proceed to factorize.
dokrbb is correct that the quadratic equation above will always work, sometimes you can factor it for a much less messy approach. Which if this was a HW problem is the approach wanted here.
So for that to equal zero, either y+3 = 0 , or y+3 = 0 (Most of the time the factors will be different.. but in this case they are the same so we'll get only 1 answer: