Make x the subject of: (a^x)/(b^1+x)=(c^3-x) I'm assuming it first has to be converted to log form some how. Can't get my head around it though, if anyone could help out that would be great. Thanks.
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Originally Posted by fibonacci111 Make x the subject of: (a^x)/(b^1+x)=(c^3-x) Please use parenthesis properly. What you wrote is $\displaystyle \frac{a^x}{b^1 + x} = c^3 - x$ -Dan
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