Thread: Solving Logarithms

How would I go about solving for "x" for something like this (should be fairly simple):



edit: thats supposed to be base 7. how would you enter the code for that?

Originally Posted by cjmac87

How would I go about solving for "x" for something like this (should be fairly simple):

if log(something) = log(something) then the somethings must be equal, the log function is one-to-one.

so just drop the logs. you have 7^x = 7^9, now what is x?

thanks that helps.

ok what about something thats not one-to-one:

Originally Posted by cjmac87

thanks that helps.

ok what about something thats not one-to-one:

you should know that

ah, oh course. very simple.

one last thing i need cleared up which is probably easy to:

can be solved how?
how about ?

Originally Posted by cjmac87

ah, oh course. very simple.

one last thing i need cleared up which is probably easy to:

can be solved how?
how about ?

then


now, you can continue..

the other one, note that



and

can you do the rest?

You seem to be missing an important concept:

Logarithm = Exponent

Trust me on this. What 2 roles are played by the 4, below?



You do the other one.