Just transfer all terms on one side. S^2 - 2HS + Z =0. It is a quadratic in S. Use the formula for solving quadratic equation and you would get the result.
Hi,
I need to know how to solve for S in the following:
S^{2}=2HS-Z
I've tried what I can think of as a current Algebra 2 student, but I can't figure it out. Plugged in to a TI-89 it shows the answer as S=(H^{2}-Z)^{1/2} -H (sorry, I don't know how to insert a square root into the equation.)