How do you factorise the following: r^3-6r^2+32 Thanks
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Okay, here's a Hint: $\displaystyle r^3-6r^2+32=r^3+(2r^2-8r^2)+(16r-16r)+32.$
I'm still confused. Is there a rule you can follow to get the correct answer? For all examples with x^3.
i think, this is an easier hint: $\displaystyle r^3 + 2r^2 - 8r^2 +32$
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