Hi
how are you?

how i can proof this equation?

(((-1)^n)(n!))/(x+n)! = ((-1)^n)(x-1)^(n+1)

thank you

The equation

$\frac{(-1)^nn!}{(x+n)!}=(-1)^n(x-1)^{n+1}$

is false for x = 0 and even n.

thank you

but how i can proof this equation
$\frac{(-1)^nn!}{(x+n)!}=(-1)^n(x-1)^{n+1}$

from left to right in Properties of the factorial??

Originally Posted by emakarov
The equation

$\frac{(-1)^nn!}{(x+n)!}=(-1)^n(x-1)^{n+1}$

is false for x = 0 and even n.
It doesn't seem to work for odd n either. I checked for n = 1, 3, 5 and x = 5 as a base case and it didn't work for them.

-Dan

$\frac{(-1)^nn!}{(x+n)!}=(-1)^n(x-1)^{n+1}$