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Need to construct an equation

Hi--I'm new to the forum (and suck at maths) and need to construct an equation for the following:

[(Sum of(A + B))/C] x [D/E] x[(Sum of (F)) to the power of the mean of G]=? Can someone please present me with the correct notation? I've tried it as follows but have no idea if it is accurate.

((∑_(k=0)^n(A+B))/T)(D/E)(∑_(k=0)^nF)^G=?

I've uploaded a jpeg attachment of what I propose but need help please...

Thanks!

Re: Need to construct an equation

Quote:

Originally Posted by

**speedbird168** Hi--I'm new to the forum (and suck at maths) and need to construct an equation for the following:

[(Sum of(A + B))/C] x [D/E] x[(Sum of (F)) to the power of the mean of G]=? Can someone please present me with the correct notation? I've tried it as follows but have no idea if it is accurate.

((∑_(k=0)^n(A+B))/T)(D/E)(∑_(k=0)^nF)^G=?

I've uploaded a jpeg attachment of what I propose but need help please...

Thanks!

I'm a bit confused here. How do A, B, C, D, E, F, and G relate to k? For example, did you mean something like

$\displaystyle \sum_{k = 0}^n \frac{A_k + B_k}{C_k}$

-Dan

Re: Need to construct an equation

Asuming that A, B, C. D , E and F are all constants, then you can see that:

$\displaystyle \sum _{k=0} ^{n} (A+B) = (A+B) + (A+B) + (A + B) + ..$ for (n+1) occurences. Hence $\displaystyle \sum _{k=0} ^{n} (A+B) = (n+1)(A+B)$.

Applying this same idea to the other summation gives:

$\displaystyle (\sum _{k=0}^{n} F)^{\mu G} = [(n+1)F]^{\mu G}$.

Putting it together:

$\displaystyle \frac {\sum _{k=0} ^{n} (A+B)} C (\frac D E) (\sum _{k=0}^{n} F)^{\mu G} = \frac {(n+1)(A+B)} C \frac D E [(n+1)F]^{\mu G} $

$\displaystyle = \frac {(n+1)^{\mu G+1}(A+B)} C \frac D {E} F^{\mu G}$

Re: Need to construct an equation

I agree that this is a bit confusing. Can you explain what the variables A, B, C, D, E, F, and G represent?