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Math Help - Solving Expression

  1. #1
    Member cmf0106's Avatar
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    Solving Expression

     A(B-1)=C solve for B

    The book states the answer is \frac{C}{A}+1 but does not show the work involved to solve it.
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  2. #2
    Junior Member Mrdavid445's Avatar
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    Re: Solving Expression

    If you start by dividing both sides by A, you get (B-1)=C/A

    Therefore by adding 1 to each side, B=(C/A)+1
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  3. #3
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    Re: Solving Expression

    It should be noted that division by A needs to be defined for this answer to be correct! This particular point needs to be emphasised, especially for beginners to elementary algebra.
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  4. #4
    Member cmf0106's Avatar
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    Re: Solving Expression

    Quote Originally Posted by Mrdavid445 View Post
    If you start by dividing both sides by A, you get (B-1)=C/A

    Therefore by adding 1 to each side, B=(C/A)+1
    The problem that trips me up on this particular problem is I try to distribute the A over the parenthesis first. Why does that not work ?
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  5. #5
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    Re: Solving Expression

    Quote Originally Posted by cmf0106 View Post
    The problem that trips me up on this particular problem is I try to distribute the A over the parenthesis first. Why does that not work ?
    It does. Assuming A\not=0,

    A(B-1)=C \Leftrightarrow AB-A=C \Leftrightarrow AB = C + A \Leftrightarrow B=\frac{C}{A}+\frac{A}{A}=\frac{C}{A}+1
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