$\displaystyle A(B-1)=C$ solve for B

The book states the answer is $\displaystyle \frac{C}{A}+1$ but does not show the work involved to solve it.

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- Apr 4th 2013, 12:55 PMcmf0106Solving Expression
$\displaystyle A(B-1)=C$ solve for B

The book states the answer is $\displaystyle \frac{C}{A}+1$ but does not show the work involved to solve it. - Apr 4th 2013, 05:23 PMMrdavid445Re: Solving Expression
If you start by dividing both sides by A, you get (B-1)=C/A

Therefore by adding 1 to each side, B=(C/A)+1 - Apr 4th 2013, 06:10 PMGusbobRe: Solving Expression
It should be noted that division by A needs to be defined for this answer to be correct! This particular point needs to be emphasised, especially for beginners to elementary algebra.

- Apr 4th 2013, 07:50 PMcmf0106Re: Solving Expression
- Apr 4th 2013, 08:07 PMGusbobRe: Solving Expression