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Math Help - Quadratic Equations with Pythagoras

  1. #1
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    Quadratic Equations with Pythagoras

    Hi,
    I was just wondering if anyone could help me.
    I have this maths equation..

    A rectangle is 3m longer than it is wide. The diagonal is 11cm. if 'x' is the width of the rectangle then:
    Use Pythagoras theorem to find an equation involving 'x' and show that it simplifies to x + 3x - 56 = 0

    Thanks
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  2. #2
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    Re: Quadratic Equations with Pythagoras

    Quote Originally Posted by janvi anish View Post
    A rectangle is 3m longer than it is wide. The diagonal is 11cm. if 'x' is the width of the rectangle then: Use Pythagoras theorem to find an equation involving 'x' and show that it simplifies to x + 3x - 56 = 0

    x^2+(x+3)^2=11^2
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  3. #3
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    Re: Quadratic Equations with Pythagoras

    hi thanks..i got this as well but then it does not work>...

    x + 3x - 56 = 0 does not = x" + (x +3)" = 11".....
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  4. #4
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    Re: Quadratic Equations with Pythagoras

    Quote Originally Posted by janvi anish View Post
    hi thanks..i got this as well but then it does not work>...

    x + 3x - 56 = 0 does not = x" + (x +3)" = 11".....

    What do you mean it does not work?
    \\x^2+(x+3)^2=11^2\\x^2+x^2+6x+9=121\\2x^2+6x-112=0\\x^2+3x-56=0
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  5. #5
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    Re: Quadratic Equations with Pythagoras

    oh god...i have been stuck for ages..i added the 9 to the 121 to make it 130...Thanks for spotting the stupid mistake i did..thks...
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