Simplify the following$\displaystyle \frac{ 2^-3(y-2)^5(y^2z)^3}{(25z^4)^{1/2}x^{-3}(y-2)^3}$. Any help would be much appreciated!

Printable View

- Apr 1st 2013, 05:07 AMMr RayonSimplifying
Simplify the following$\displaystyle \frac{ 2^-3(y-2)^5(y^2z)^3}{(25z^4)^{1/2}x^{-3}(y-2)^3}$. Any help would be much appreciated!

- Apr 1st 2013, 05:30 AMHallsofIvyRe: Simplifying
Who ever gave you this problem clearly expects you to know the "laws of exponents" (also called "index laws").

$\displaystyle a^xa^y= a^{x+y}$

$\displaystyle \frac{a^x}{a^y}= a^{x- y}$

$\displaystyle (a^x)^y= a^{xy}$

Use those to combine powers of the same base.