$\displaystyle \frac{x}{x+8}=\frac{2}{3}$

The answer is $\displaystyle x=16$ but I can't see how they're coming to this answer...

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- Mar 26th 2013, 07:48 AMuperkurkFractions just can't think of what to do here
$\displaystyle \frac{x}{x+8}=\frac{2}{3}$

The answer is $\displaystyle x=16$ but I can't see how they're coming to this answer... - Mar 26th 2013, 07:53 AMPlatoRe: Fractions just can't think of what to do here
- Mar 26th 2013, 08:14 AMuperkurkRe: Fractions just can't think of what to do here
- Mar 26th 2013, 10:08 AMHallsofIvyRe: Fractions just can't think of what to do here
The reason for "$\displaystyle x\ne -8$" is that, in that case, the fraction on the left is not defined.

And you go from one equation to the other by multiplying both sides by 3(x+ 8), the product of the two denominators.