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Math Help - Weird problem with my problem

  1. #1
    Senior Member Paze's Avatar
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    Weird problem with my problem

    \frac{sinx+1}{sinx+1} if I call (sinx+1)=a then we have \frac{a}{a}=1 however when I split the original problem up I get \frac{sinx}{sinx}+\frac{1}{1}=2 I know I am just doing something silly but what is it?
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  2. #2
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    Re: Weird problem with my problem

    Paze
    is this a type of joke? how you split the fraction?
    please respect the rules of algebra...there is no such split...you have to split sinx/(sinx+1) then 1/(sinx+1)
    and of course it will never give you 2.....
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  3. #3
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    Re: Weird problem with my problem

    \frac{a+1}{a+1}= 1 for any a\ne -1. No, \frac{a+1}{a+ 1}\ne \frac{a}{a}+ \frac{1}{1}= 2.
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  4. #4
    Senior Member Paze's Avatar
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    Re: Weird problem with my problem

    Haha of course. Why the hell couldn't I spot the obvious issue. I know these rules like the back of my hand...
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