$\displaystyle \frac{sinx+1}{sinx+1}$ if I call $\displaystyle (sinx+1)=a$ then we have $\displaystyle \frac{a}{a}=1$ however when I split the original problem up I get $\displaystyle \frac{sinx}{sinx}+\frac{1}{1}=2$ I know I am just doing something silly but what is it?