# Weird problem with my problem

• Mar 21st 2013, 01:04 PM
Paze
Weird problem with my problem
$\displaystyle \frac{sinx+1}{sinx+1}$ if I call $\displaystyle (sinx+1)=a$ then we have $\displaystyle \frac{a}{a}=1$ however when I split the original problem up I get $\displaystyle \frac{sinx}{sinx}+\frac{1}{1}=2$ I know I am just doing something silly but what is it?
• Mar 21st 2013, 01:20 PM
MINOANMAN
Re: Weird problem with my problem
Paze
is this a type of joke? how you split the fraction?
please respect the rules of algebra...there is no such split...you have to split sinx/(sinx+1) then 1/(sinx+1)
and of course it will never give you 2.....
• Mar 21st 2013, 01:24 PM
HallsofIvy
Re: Weird problem with my problem
$\displaystyle \frac{a+1}{a+1}= 1$ for any $\displaystyle a\ne -1$. No, $\displaystyle \frac{a+1}{a+ 1}\ne \frac{a}{a}+ \frac{1}{1}= 2$.
• Mar 21st 2013, 02:19 PM
Paze
Re: Weird problem with my problem
Haha of course. Why the hell couldn't I spot the obvious issue. I know these rules like the back of my hand...