I have to solve that equation :

11^{n}-2^{n}=k^{2}

where n,k are from N .

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- Mar 19th 2013, 07:43 AMstephanxA pretty hard problem .. please help
I have to solve that equation :

11^{n}-2^{n}=k^{2}

where n,k are from N . - Mar 19th 2013, 07:48 AMShakarriRe: A pretty hard problem .. please help
Well by observation n=1, k=3 is one solution. I don't think there are other solutions but I have no way of proving their aren't

- Mar 19th 2013, 07:57 AMstephanxRe: A pretty hard problem .. please help
Yes , I have also find that . And n can be also =0 and k=0 .

So there are only 2 solutions,I think .. but how should I demonstrate ? - Mar 19th 2013, 08:45 AMShakarriRe: A pretty hard problem .. please help
0 is generally not considered a natural number

- Mar 19th 2013, 09:03 AMPlatoRe: A pretty hard problem .. please help
"There is no universal agreement about whether to include zero in the set of natural numbers: some define the natural numbers to be the positive integers {1, 2, 3, ...}, while for others the term designates the non-negative integers {0, 1, 2, 3, ...}. The former definition is the traditional one, with the latter definition having first appeared in the 19th century. Some authors use the term natural number to exclude 0 and whole number to include it; others use whole number in a way that includes both 0 and the negative integers, i.e., as an equivalent of the integer term."

See this web entry.

I have a great many different textbooks on*set theory*. In the vast majority of them use . - Mar 19th 2013, 09:05 AMShakarriRe: A pretty hard problem .. please help
It's one of the things in mathematics that irks me :(

- Mar 19th 2013, 09:59 AMstephanxRe: A pretty hard problem .. please help
Ok , firstly , thanks for the explanation . I've read the article about the natural numbers about one year ago :)

I haven't seen that the author had mentioned that the numbers are different from 0 . And also , in the some problems that i've seen if the numbers aren't null they are included in N* and in the problem the number are only from N .