how can i solve this exercise? ( The value of an investment varies according to the formula V=A^t/12,where V is the value of the investment in pounds, A is the constant to be found and t is the time in years after the investment was made. i)If the investment was worth 8000 pounds after three years,how much the value of A to the nearest pound is? ii)How much the value of the investment after 10 years will be?
Mar 16th 2013, 07:30 AM
Raise both sides to the power of
Remember the rules of indices. the indices and cancel to be just 1
You can now find A.
After you find the constant A you can do the second part easily by using the original equation at t=10
Mar 16th 2013, 01:29 PM
shakari,,tell me what will be the answers with the data what i have written above..
Mar 16th 2013, 01:43 PM
You'll learn more if you do it yourself :)
Mar 17th 2013, 03:00 AM
well if v=8000,then A=8000^4,in the first question, this is impossible..so plz tell me the answers