Solve the following over the real numbers.
a) -2 = (-5x/12) + 3
b) 3x + 5 ≥ 6x – 7
c) 3x + √6 = 2x - 3√6
Subtract -3 from both sides, then divide both sides by -5/12
Subtract 3x from both sides, then add 7 to both sides, then divide both sides by 3b) 3x + 5 ≥ 6x – 7
Subtract 2x from both sides, then subtract $\displaystyle \sqrt{6}$ from both sidesc) 3x + √6 = 2x - 3√6