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Math Help - linear equation involving one unknown

  1. #1
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    linear equation involving one unknown

    Nelly has only 20 cent and 50 cent coins. The number of 20 cent coins is 23 more than the 50 cent coins. their total value is 26.30$. How many 50 cent coins does she have?
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  2. #2
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    Re: linear equation involving one unknown

    Normally, I would set this up by letting x be the number of 20 cent coins and y be the number of 50 cent coins. But you titled this "linear equation involving one unknown" so let x be the number of 20 cent coins. Since "the number of 20 cent coins is 23 more than the number of 50 cent coins", the number of 50 cent coins is x- 23. The value of all the coins is 20x+ 50(x- 23) and that is 26.20$. Assuming that 1.00$ is "100 cents" (what currency is this?), the equation is 20x+ 50(x- 23)= 2620.
    Last edited by HallsofIvy; March 13th 2013 at 08:04 AM.
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